lintCode (76) Longest Increasing Subsequence

Given a sequence of integers, find the longest increasing subsequence (LIS).

You code should return the length of the LIS.

Have you met this question in a real interview? 

Yes

Example

For [5, 4, 1, 2, 3], the LIS  is [1, 2, 3], return 3

For [4, 2, 4, 5, 3, 7], the LIS is [4, 4, 5, 7], return 4

Challenge

Time complexity O(n^2) or O(nlogn)

Clarification

What's the definition of longest increasing subsequence?

    * The longest increasing subsequence problem is to find a subsequence of a given sequence in which the subsequence's elements are in sorted order, lowest to highest, and in which the subsequence is as long as possible. This subsequence is not necessarily contiguous, or unique.  

    * https://en.wikipedia.org/wiki/Longest_common_subsequence_problem

f[i] = 0 to i max subsequence

initial state f[0]=1

update: f[i] = max(f[j] if a[j]<=a[i]) +1

result: max(f[i])

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28

class Solution { public: /** * @param nums: The integer array * @return: The length of LIS (longest increasing subsequence) */ int longestIncreasingSubsequence(vector<int> nums) { // write your code here int n=nums.size(); if (n==0) return 0; vector<int> tbl(n, 1); for (int i=1; i<n; i++){ int val=INT_MIN; for(int j=0; j<i; j++){ if (nums[i]>=nums[j]) val=max(val, tbl[j]); } if (val!=INT_MIN) tbl[i]=val+1; } int result=INT_MIN; for (int i=0; i<n; i++){ result=max(result, tbl[i]); } return result; } };